Question

which element has an electron configuration ending in 4p^5? select the correct answer below: br se i kr

Explanation:

The principal quantum number \(n = 4\) indicates the fourth - energy level and the \(p\) sub - shell with 5 electrons. Bromine (Br) has an electron configuration that ends in \(4p^{5}\). Selenium (Se) has an electron configuration ending in \(4p^{4}\), iodine (I) in \(5p^{5}\), and krypton (Kr) in \(4p^{6}\).

Answer:

Br