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which quadratic function in standard form has the values $a = -3.5$, $b…

Question

which quadratic function in standard form has the values $a = -3.5$, $b = 2.7$, and $c = -8.2$?
$\circ$ $f(x) = 2.7x^2 - 8.2x - 3.5$
$\circ$ $f(x) = 2.7x^2 - 3.5x - 8.2$
$\circ$ $f(x) = -3.5x^2 - 8.2x + 2.7$
$\circ$ $f(x) = -3.5x^2 + 2.7x - 8.2$

Explanation:

Step1: Recall standard form of quadratic function

The standard form of a quadratic function is \( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are the coefficients.

Step2: Substitute given values

We are given \( a = -3.5 \), \( b = 2.7 \), and \( c = -8.2 \). Substituting these into the standard form, we get \( f(x) = -3.5x^2 + 2.7x - 8.2 \).

Answer:

\( f(x) = -3.5x^2 + 2.7x - 8.2 \) (the fourth option)