Question

which values of m and b will create a system of equations with no solution? select two options.$y = mx + b$$y = -2x + \frac{3}{2}$

Explanation:

Step1: Recall no-solution condition

A system of linear equations $y=m_1x+b_1$ and $y=m_2x+b_2$ has no solution if they are parallel (equal slopes, $m_1=m_2$) and have different y-intercepts ($b_1
eq b_2$).

Step2: Match slope

For the given equation $y=-2x+\frac{3}{2}$, the slope is $-2$, so $m=-2$.

Step3: Choose valid y-intercepts

The y-intercept of the given line is $\frac{3}{2}$, so $b$ can be any value not equal to $\frac{3}{2}$ (e.g., $b=1$, $b=4$, $b=-1$, etc.).

Answer:

Any pair where $m=-2$ and $b
eq\frac{3}{2}$. For example:

1. $m=-2$, $b=1$
2. $m=-2$, $b=4$