write the correct name for each of these compounds: 12. fe(oh)₂ 13. (nh₄)₃po₄ 14. alpo₄ 15. na₃po₃ 16. cu(c₂h₃o₂)₂ 17. caco₃ 18. fe₂o₃ 19. feo 20. nh₄oh 21. si(so₄)₂

Question

Accepted Answer

### 12. $\boldsymbol{\ce{Fe(OH)2}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{Fe^{2+}}$ (Iron(II) ion, since hydroxide has -1 charge, 2 hydroxides give -2, so Fe is +2). Anion: $\ce{OH^-}$ (Hydroxide ion).
## Step2: Name the compound
Name the cation (with charge indicated by Roman numeral if needed) and then the anion. So Iron(II) hydroxide.
# Answer: Iron(II) hydroxide

### 13. $\boldsymbol{\ce{(NH4)3PO4}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{NH4^+}$ (Ammonium ion). Anion: $\ce{PO4^{3-}}$ (Phosphate ion).
## Step2: Name the compound
Name the cation and then the anion. Ammonium phosphate.
# Answer: Ammonium phosphate

### 14. $\boldsymbol{\ce{AlPO4}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{Al^{3+}}$ (Aluminum ion, charge is +3, no Roman numeral needed as Al has only +3). Anion: $\ce{PO4^{3-}}$ (Phosphate ion).
## Step2: Name the compound
Aluminum phosphate.
# Answer: Aluminum phosphate

### 15. $\boldsymbol{\ce{Na3PO3}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{Na^+}$ (Sodium ion). Anion: $\ce{PO3^{3-}}$ (Phosphite ion).
## Step2: Name the compound
Sodium phosphite.
# Answer: Sodium phosphite

### 16. $\boldsymbol{\ce{Cu(C2H3O2)2}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{Cu^{2+}}$ (Copper(II) ion, since each acetate is -1, 2 acetates give -2, so Cu is +2). Anion: $\ce{C2H3O2^-}$ (Acetate ion).
## Step2: Name the compound
Copper(II) acetate.
# Answer: Copper(II) acetate

### 17. $\boldsymbol{\ce{CaCO3}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{Ca^{2+}}$ (Calcium ion). Anion: $\ce{CO3^{2-}}$ (Carbonate ion).
## Step2: Name the compound
Calcium carbonate.
# Answer: Calcium carbonate

### 18. $\boldsymbol{\ce{Fe2O3}}$
# Explanation:
## Step1: Determine Fe charge
O is -2, 3 O atoms: $3	imes(-2)= -6$. Let Fe charge be x, 2 Fe atoms: $2x + (-6)=0\Rightarrow x = +3$. So $\ce{Fe^{3+}}$ (Iron(III) ion). Anion: $\ce{O^{2-}}$ (Oxide ion).
## Step2: Name the compound
Iron(III) oxide.
# Answer: Iron(III) oxide

### 19. $\boldsymbol{\ce{FeO}}$
# Explanation:
## Step1: Determine Fe charge
O is -2, so Fe is +2 (since $x + (-2)=0\Rightarrow x = +2$). $\ce{Fe^{2+}}$ (Iron(II) ion). Anion: $\ce{O^{2-}}$ (Oxide ion).
## Step2: Name the compound
Iron(II) oxide.
# Answer: Iron(II) oxide

### 20. $\boldsymbol{\ce{NH4OH}}$
# Explanation:
## Step1: Identify cation and anion
Cation: $\ce{NH4^+}$ (Ammonium ion). Anion: $\ce{OH^-}$ (Hydroxide ion).
## Step2: Name the compound
Ammonium hydroxide (also known as aqueous ammonia, but the ionic compound name is ammonium hydroxide).
# Answer: Ammonium hydroxide

### 21. $\boldsymbol{\ce{Si(SO4)2}}$
# Explanation:
## Step1: Determine Si charge
$\ce{SO4^{2-}}$ (Sulfate ion), 2 sulfate ions: $2	imes(-2)= -4$. So Si is +4 (since $x + (-4)=0\Rightarrow x = +4$). $\ce{Si^{4+}}$ (Silicon ion, charge +4). Anion: $\ce{SO4^{2-}}$ (Sulfate ion).
## Step2: Name the compound
Silicon(IV) sulfate (or sometimes just silicon sulfate, but charge is indicated for clarity).
# Answer: Silicon(IV) sulfate

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QUESTION IMAGE

Question

Explanation:

12. $\boldsymbol{\ce{Fe(OH)2}}$

Step1: Identify cation and anion

Step2: Name the compound

Step1: Identify cation and anion

Step2: Name the compound

Step1: Identify cation and anion

Step2: Name the compound

Answer:

13. $\boldsymbol{\ce{(NH4)3PO4}}$