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Question
- if you spill a little of the unknown as you mix it with the water, will the molecular weight that you calculate be too high or too low? why? (1pts)
When the unknown is mixed with water due to spillage, the mass - related measurements used in molecular weight calculations (such as mass of solute for colligative - property based molecular weight determinations) will be affected. If we assume methods like boiling - point elevation or freezing - point depression for molecular weight calculation, the presence of extra water changes the concentration of the solution. Since molecular weight is inversely related to the molality in colligative - property equations, the calculated molecular weight will be too low. This is because the measured colligative property change (e.g., $\Delta T_b$ or $\Delta T_f$) will be less than what it should be for the pure unknown sample, leading to a lower calculated number of moles and thus a lower calculated molecular weight.
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The calculated molecular weight will be too low because the presence of extra water from the spillage dilutes the unknown, reducing the magnitude of the colligative property change used in the molecular weight calculation.