Question

1. a 0.003 m³ object is submerged in freshwater (density = 1000 kg/m³). calculate the buoyant force. use g = 9.8 m/s².

Explanation:

Step1: Recall buoyant - force formula

The formula for buoyant force is $F_b=
ho Vg$, where $
ho$ is the density of the fluid, $V$ is the volume of the fluid displaced (equal to the volume of the submerged object in this case), and $g$ is the acceleration due to gravity.

Step2: Substitute given values

We are given that $
ho = 1000\ kg/m^3$, $V=0.003\ m^3$, and $g = 9.8\ m/s^2$. Substitute these values into the formula: $F_b=1000\times0.003\times9.8$.

Step3: Calculate the result

$F_b = 1000\times0.003\times9.8=29.4\ N$.

Answer:

$29.4\ N$