Question

09/03 - segment bisector practice l (updated)
line l bisects each segment. set up an equation to find x and then find the specified lengths.
equation: (no spaces)
x = jt = tk = jk =

Explanation:

Step1: Use bisection property

Since line $l$ bisects segment $JK$, we have $JT = TK$. So the equation is $3x + 6=15$.

Step2: Solve for $x$

Subtract 6 from both sides of the equation $3x + 6=15$: $3x=15 - 6$, so $3x = 9$. Then divide both sides by 3, we get $x=\frac{9}{3}=3$.

Step3: Find $JT$

Substitute $x = 3$ into the expression for $JT$. $JT=3x + 6=3\times3+6=9 + 6=15$.

Step4: Find $TK$

Since $TK = 15$ (from the given and bisection property).

Step5: Find $JK$

$JK=JT + TK=15+15 = 30$.

Answer:

Equation: $3x + 6=15$
$x = 3$
$JT = 15$
$TK = 15$
$JK = 30$