QUESTION IMAGE
Question
- $4xy^{3} \cdot 2x^{3}$
- $(3n)^{4}$
- $(2n^{2})^{2}$
- $\frac{4xy^{4}}{4x^{3}y^{2}}$
- $\frac{x^{3}y^{4}}{4y^{4}}$
- $-\frac{2r^{4}}{4r^{2}}$
- $\frac{-2b^{4}}{-b^{3}}$
Step1: Multiply coefficients, combine $x$ terms
$4 \cdot 2 \cdot x^{1+3} y^3 = 8x^4y^3$
Step2: Distribute exponent to factors
$3^4 n^4 = 81n^4$
Step3: Distribute exponent to factors
$2^2 (n^2)^2 = 4n^{4}$
Step4: Simplify coefficients, subtract exponents
$\frac{4}{4} x^{1-3} y^{4-2} = x^{-2}y^2 = \frac{y^2}{x^2}$
Step5: Cancel $y^4$, simplify coefficient
$\frac{x^3}{4} \cdot \frac{y^4}{y^4} = \frac{x^3}{4}$
Step6: Simplify coefficients, subtract exponents
$-\frac{2}{4} r^{4-2} = -\frac{1}{2}r^2$
Step7: Cancel negatives, subtract exponents
$\frac{-2}{-1} b^{4-3} = 2b$
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- $8x^4y^3$
- $81n^4$
- $4n^4$
- $\frac{y^2}{x^2}$
- $\frac{x^3}{4}$
- $-\frac{1}{2}r^2$
- $2b$