Question

10
11 cm.
10 cm.
8 cm.
16 cm.
11
17 cm.
38 cm.
26 cm.
12
10 km.
22 km.
17 km.

Explanation:

Step1: Calculate area of trapezoid (Q10)

Use trapezoid area formula: $\text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height}$
First find height: Use Pythagoras on right triangle: $h = \sqrt{11^2 - (16-10)^2} = \sqrt{121-36} = \sqrt{85} \approx 9.22$
$\text{Area} = \frac{1}{2} \times (10+16) \times 9.22 = 13 \times 9.22 = 119.86$
(Note: If using the given 188.5, the height would be $\frac{2 \times 188.5}{10+16} = 14.5$, which does not match the side 11 cm. Assuming the task is to verify or recalculate, but proceeding with given figure values)

Step2: Calculate area of kite (Q11)

Use kite area formula: $\text{Area} = \frac{1}{2} \times d_1 \times d_2$
$\text{Area} = \frac{1}{2} \times 26 \times 38 = 13 \times 38 = 494$
(Note: The given 1840 would imply $d_1 \times d_2 = 3680$, which does not match the provided diagonals. Proceeding with figure values)

Step3: Calculate area of kite (Q12)

Use kite area formula: $\text{Area} = \frac{1}{2} \times d_1 \times d_2$
First find full diagonal: $d_1 = 22 \times 2 = 44$
$\text{Area} = \frac{1}{2} \times 44 \times 17 = 22 \times 17 = 374$
(Note: The given 94.5 does not align with figure values. Proceeding with figure measurements)

Answer:

1. Area of trapezoid (Q10): $\approx 119.86$ cm²
2. Area of kite (Q11): $494$ cm²
3. Area of kite (Q12): $374$ km²

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If using the pre-filled values as the intended answers: