Question

10.) consider someone who takes a fall from 6 feet. assume they undergo freefall during the entire 6 foot fall, how fast are they going upon impact?

Explanation:

Step1: List known values

Displacement $h = 6$ ft, gravitational acceleration $g = 32$ ft/s², initial velocity $v_0 = 0$ ft/s

Step2: Select kinematic equation

Use $v^2 = v_0^2 + 2gh$ (relates velocity, acceleration, displacement)

Step3: Substitute values into equation

$v^2 = 0^2 + 2 \times 32 \times 6$
$v^2 = 384$

Step4: Solve for final velocity

$v = \sqrt{384} = 8\sqrt{6}$

Answer:

$8\sqrt{6}$ ft/s (or approximately 19.6 ft/s)