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10. for each reaction below, identify the reaction type (synthesis, dec…

Question

  1. for each reaction below, identify the reaction type (synthesis, decomposition, single replacement, double replacement, combustion):

a. $2h_2 + o_2 \
ightarrow 2h_2o$
b. $caco_3 \
ightarrow cao + co_2$
c. $ch_4 + 2o_2 \
ightarrow co_2 + 2h_2o$

  1. a hydrocarbon undergoes complete combustion.

a. what two products must always be formed?
b. why does oxygen always appear as a reactant?

  1. a reaction produces carbon dioxide, water, and a large amount of heat and light.

a. what type of reaction is this most likely?
b. what clues in the description helped you identify it?

Explanation:

Response
Question 10
Part a

Step1: Recall reaction type definitions

Synthesis: \( A + B
ightarrow AB \). Decomposition: \( AB
ightarrow A + B \). Single replacement: \( A + BC
ightarrow AC + B \). Double replacement: \( AB + CD
ightarrow AD + CB \). Combustion: \( \text{Hydrocarbon} + \text{O}_2
ightarrow \text{CO}_2 + \text{H}_2\text{O} \) (usually). Here, \( 2\text{H}_2 + \text{O}_2
ightarrow 2\text{H}_2\text{O} \) is two substances forming one, so synthesis.

Step2: Confirm with formula

Reactants: \( \text{H}_2 \) and \( \text{O}_2 \) (two elements), product: \( \text{H}_2\text{O} \) (compound). Matches synthesis (\( A + B
ightarrow AB \)).

Step1: Recall decomposition definition

Decomposition is one compound breaking into two or more substances. Here, \( \text{CaCO}_3
ightarrow \text{CaO} + \text{CO}_2 \) is one compound forming two.

Step2: Check formula

Reactant: \( \text{CaCO}_3 \) (compound), products: \( \text{CaO} \) and \( \text{CO}_2 \) (two substances). Matches decomposition (\( AB
ightarrow A + B \)).

Step1: Recall combustion definition

Combustion involves a hydrocarbon (here \( \text{CH}_4 \)) reacting with \( \text{O}_2 \) to form \( \text{CO}_2 \) and \( \text{H}_2\text{O} \). The reaction \( \text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O} \) fits this.

Step2: Confirm with formula

Reactants: \( \text{CH}_4 \) (hydrocarbon) and \( \text{O}_2 \), products: \( \text{CO}_2 \) and \( \text{H}_2\text{O} \). Matches combustion.

Answer:

Synthesis

Part b