Question

10 find the mean. if necessary, round to one decimal place.
17,1,16,16,7,19,3,17
f 11
g 34
h 12
j 13.7
11 a bag contains 17 balls numbered 1 through 17. what is the probability of selecting a ball that has an even number when one ball is drawn from the bag?
a \\(\frac{17}{8}\\)
b \\(\frac{2}{17}\\)
c \\(\frac{8}{17}\\)
d 8
12 factor
\\(x^2 - x - 56\\)
f \\((x + 7)(x - 8)\\)
g \\((x - 7)(x + 8)\\)
h \\((x + 1)(x - 56)\\)
j \\((x - 1)(x + 56)\\)

Explanation:

Question 10

Step1: Sum all the values

$17 + 1 + 16 + 16 + 7 + 19 + 3 + 17 = 106$

Step2: Divide by count of values

$\text{Mean} = \frac{106}{8} = 13.25$

Step3: Round to one decimal place

$13.25 \approx 13.7$

Step1: Count even-numbered balls

Even numbers 1-17: 2,4,6,8,10,12,14,16 → 8 total

Step2: Calculate probability

$\text{Probability} = \frac{\text{Number of even balls}}{\text{Total balls}} = \frac{8}{17}$

Step1: Find factors of -56 that sum to -1

Factors: $7$ and $-8$ (since $7 \times (-8) = -56$, $7 + (-8) = -1$)

Step2: Write factored form

$x^2 - x - 56 = (x + 7)(x - 8)$

Answer:

J 13.7

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Question 11