QUESTION IMAGE
Question
- given $f(x) = \frac{3}{4}x - 6$
find $f(8) = $
find $x$ so that $f(x) = 18$
- given $h(x) = \frac{2}{3}x - 4$ fill in the table.
\
$$\begin{tabular}{|c|c|}
\\hline
$x$ & $h(x)$ \\\\
\\hline
12 & \\\\
\\hline
-3 & \\\\
\\hline
& 24 \\\\
\\hline
\\end{tabular}$$
- solve for $y$ then state the slope of the line. $4x - 3y = 15$
$m = $
Step1: Substitute x=8 into f(x)
$f(8) = \frac{3}{4}(8) - 6$
Step2: Calculate f(8)
$f(8) = 6 - 6 = 0$
Step3: Set f(x)=18, solve for x
$\frac{3}{4}x - 6 = 18$
Step4: Isolate the x-term
$\frac{3}{4}x = 18 + 6 = 24$
Step5: Solve for x
$x = 24 \times \frac{4}{3} = 32$
Step6: Substitute x=12 into h(x)
$h(12) = \frac{2}{3}(12) - 4$
Step7: Calculate h(12)
$h(12) = 8 - 4 = 4$
Step8: Substitute x=-3 into h(x)
$h(-3) = \frac{2}{3}(-3) - 4$
Step9: Calculate h(-3)
$h(-3) = -2 - 4 = -6$
Step10: Set h(x)=24, solve for x
$\frac{2}{3}x - 4 = 24$
Step11: Isolate the x-term
$\frac{2}{3}x = 24 + 4 = 28$
Step12: Solve for x
$x = 28 \times \frac{3}{2} = 42$
Step13: Rearrange 4x-3y=15 to solve for y
$-3y = -4x + 15$
Step14: Solve for y
$y = \frac{4}{3}x - 5$
Step15: Identify slope from y=mx+b
Slope $m = \frac{4}{3}$
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- $f(8) = 0$
- $x = 32$
- For $h(x)$ table:
- When $x=12$, $h(x)=4$
- When $x=-3$, $h(x)=-6$
- When $h(x)=24$, $x=42$
- Solved for $y$: $y = \frac{4}{3}x - 5$; Slope $m = \frac{4}{3}$