Question

1. $y = 3(x - 2)^2 - 3$

no calculators
then describe the transformat
$y = x^2 - 6$ $y = (x + 4)^2$

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a parabola is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex and the axis of symmetry is \( x = h \).

Step2: Identify \( h \) and \( k \) from given equation

For the equation \( y = 3(x - 2)^2 - 3 \), comparing with \( y = a(x - h)^2 + k \), we have \( h = 2 \) and \( k = -3 \). So the vertex is \((2, -3)\) and the axis of symmetry is \( x = 2 \).

Answer:

Vertex: \((2, -3)\), Axis of Symmetry: \( x = 2 \)