Question

1. what is the area, in square feet, of the isosceles trapezoid below? 15.7 ft 8 ft 5.7 ft

Explanation:

Step1: Recall trapezoid area formula

The formula for the area of a trapezoid is $A=\frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the parallel - sides and $h$ is the height.

Step2: Identify values

Here, $b_1 = 15.7$ ft, $b_2 = 5.7$ ft, and $h = 8$ ft.

Step3: Substitute values into formula

$A=\frac{1}{2}(15.7 + 5.7)\times8$.
First, calculate the sum of the parallel sides: $15.7+5.7 = 21.4$ ft.
Then, multiply by $\frac{1}{2}$ and the height: $A=\frac{1}{2}\times21.4\times8=21.4\times4$.
$A = 85.6$ square feet.

Answer:

$85.6$ square feet