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10x = 8.2·10 - 47\ 10x = 52 - 47\ ide both sides by what?\ \\(\\dfrac{1…

Question

10x = 8.2·10 - 47\
10x = 52 - 47\
ide both sides by what?\
\\(\dfrac{10x}{\square}=\dfrac{5}{\square}\\)

Explanation:

Step1: Analyze the equation structure

We have the equation \(\frac{10x}{\square}=\frac{5}{\square}\). To solve for \(x\), we need to perform an operation that isolates \(x\). Looking at the left - hand side, the coefficient of \(x\) is \(10\) (from \(10x\)). If we divide both sides by \(10\), we can simplify the left - hand side to \(x\) (since \(\frac{10x}{10}=x\)) and the right - hand side will be \(\frac{5}{10}\) (or \(\frac{1}{2}\) if we simplify further).

Step2: Confirm the operation

In the context of solving linear equations (or in this case, a proportion - like equation), when we have a term with a coefficient (here \(10x\)) and we want to get \(x\) alone, we divide by the coefficient of \(x\), which is \(10\). So we divide both sides by \(10\).

Answer:

We divide both sides by \(10\). So the boxes should be filled with \(10\) (i.e., \(\frac{10x}{10}=\frac{5}{10}\)).