Question

1. $y = 7 - 4x$

$x$	$y$
1
2
3
4

1. $y = \frac{x}{3} + 2$

$x$	$y$

1. $y = \frac{3}{2}x - 2$

$x$	$y$

Explanation:

Problem 11: \( y = 7 - 4x \)

Step1: Substitute \( x = 0 \)

\( y = 7 - 4(0) = 7 \)

Step2: Substitute \( x = 1 \)

\( y = 7 - 4(1) = 3 \)

Step3: Substitute \( x = 2 \)

\( y = 7 - 4(2) = -1 \)

Step4: Substitute \( x = 3 \)

\( y = 7 - 4(3) = -5 \)

Step5: Substitute \( x = 4 \)

\( y = 7 - 4(4) = -9 \)

Step1: Substitute \( x = -3 \)

\( y = \frac{-3}{3} + 2 = -1 + 2 = 1 \)

Step2: Substitute \( x = 0 \)

\( y = \frac{0}{3} + 2 = 0 + 2 = 2 \)

Step3: Substitute \( x = 3 \)

\( y = \frac{3}{3} + 2 = 1 + 2 = 3 \)

Step4: Substitute \( x = 6 \)

\( y = \frac{6}{3} + 2 = 2 + 2 = 4 \)

Step5: Substitute \( x = 9 \)

\( y = \frac{9}{3} + 2 = 3 + 2 = 5 \)

Step1: Substitute \( x = -2 \)

\( y = \frac{3}{2}(-2) - 2 = -3 - 2 = -5 \)

Step2: Substitute \( x = 0 \)

\( y = \frac{3}{2}(0) - 2 = 0 - 2 = -2 \)

Step3: Substitute \( x = 2 \)

\( y = \frac{3}{2}(2) - 2 = 3 - 2 = 1 \)

Step4: Substitute \( x = 4 \)

\( y = \frac{3}{2}(4) - 2 = 6 - 2 = 4 \)

Step5: Substitute \( x = 6 \)

\( y = \frac{3}{2}(6) - 2 = 9 - 2 = 7 \)

Answer:

\( x \)	\( y \)
1	3
2	-1
3	-5
4	-9

Problem 13: \( y = \frac{x}{3} + 2 \) (Let's choose \( x = -3, 0, 3, 6, 9 \) for simplicity)