QUESTION IMAGE
Question
- fill in the following table. be careful, it contains atoms, ions and isotopes.
| isotopic notation | atomic # | mass # | # of protons | # of electrons | # of neutrons | net charge | cation / anion |
|---|---|---|---|---|---|---|---|
| $^{108}_{47}ag^{1 + }$ | 46 | ||||||
| 30 | 35 | 0 | |||||
| 55 | 133 | 3+ | |||||
| $^{31}_{15}p^{3 - }$ |
Step1: Recall atomic number properties
The atomic number is equal to the number of protons. Given atomic number = 13, so number of protons = 13. Mass number = number of protons+number of neutrons. So mass number = 13 + 15=28. Since number of protons = number of electrons = 13, net charge = 0 and it's a neutral atom. Isotopic notation: $^{28}_{13}Al$.
Step2: Analyze silver - ion
For $^{108}_{47}Ag^{1 + }$, atomic number = 47, so number of protons = 47. Mass number = 108. Number of electrons = 46 (as it has a + 1 charge). Number of neutrons=mass number - number of protons = 108 - 47 = 61. Net charge = + 1 and it's a cation.
Step3: Determine neutral - atom details
If number of protons = 30, atomic number = 30. Element is zinc. Mass number = number of protons+number of neutrons = 30 + 35 = 65. Since net charge = 0, number of electrons = 30. Isotopic notation: $^{65}_{30}Zn$.
Step4: Analyze ion with 3+ charge
Atomic number = 55, so number of protons = 55. Mass number = 133. Number of neutrons = 133 - 55 = 78. Since net charge = 3 +, number of electrons = 55 - 3=52. It's a cation. Isotopic notation: $^{133}_{55}Cs^{3 + }$.
Step5: Analyze phosphorus - ion
For $^{31}_{15}P^{3 - }$, atomic number = 15, so number of protons = 15. Mass number = 31. Number of neutrons = 31 - 15 = 16. Since it has a - 3 charge, number of electrons = 15+3 = 18. Net charge=-3 and it's an anion.
| Isotopic Notation | Atomic # | Mass # | # of Protons | # of Electrons | # of Neutrons | Net Charge | Cation / Anion |
|---|---|---|---|---|---|---|---|
| $^{108}_{47}Ag^{1 + }$ | 47 | 108 | 47 | 46 | 61 | + 1 | Cation |
| $^{65}_{30}Zn$ | 30 | 65 | 30 | 30 | 35 | 0 | Neutral |
| $^{133}_{55}Cs^{3 + }$ | 55 | 133 | 55 | 52 | 78 | + 3 | Cation |
| $^{31}_{15}P^{3 - }$ | 15 | 31 | 15 | 18 | 16 | - 3 | Anion |
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Step1: Recall atomic number properties
The atomic number is equal to the number of protons. Given atomic number = 13, so number of protons = 13. Mass number = number of protons+number of neutrons. So mass number = 13 + 15=28. Since number of protons = number of electrons = 13, net charge = 0 and it's a neutral atom. Isotopic notation: $^{28}_{13}Al$.
Step2: Analyze silver - ion
For $^{108}_{47}Ag^{1 + }$, atomic number = 47, so number of protons = 47. Mass number = 108. Number of electrons = 46 (as it has a + 1 charge). Number of neutrons=mass number - number of protons = 108 - 47 = 61. Net charge = + 1 and it's a cation.
Step3: Determine neutral - atom details
If number of protons = 30, atomic number = 30. Element is zinc. Mass number = number of protons+number of neutrons = 30 + 35 = 65. Since net charge = 0, number of electrons = 30. Isotopic notation: $^{65}_{30}Zn$.
Step4: Analyze ion with 3+ charge
Atomic number = 55, so number of protons = 55. Mass number = 133. Number of neutrons = 133 - 55 = 78. Since net charge = 3 +, number of electrons = 55 - 3=52. It's a cation. Isotopic notation: $^{133}_{55}Cs^{3 + }$.
Step5: Analyze phosphorus - ion
For $^{31}_{15}P^{3 - }$, atomic number = 15, so number of protons = 15. Mass number = 31. Number of neutrons = 31 - 15 = 16. Since it has a - 3 charge, number of electrons = 15+3 = 18. Net charge=-3 and it's an anion.
| Isotopic Notation | Atomic # | Mass # | # of Protons | # of Electrons | # of Neutrons | Net Charge | Cation / Anion |
|---|---|---|---|---|---|---|---|
| $^{108}_{47}Ag^{1 + }$ | 47 | 108 | 47 | 46 | 61 | + 1 | Cation |
| $^{65}_{30}Zn$ | 30 | 65 | 30 | 30 | 35 | 0 | Neutral |
| $^{133}_{55}Cs^{3 + }$ | 55 | 133 | 55 | 52 | 78 | + 3 | Cation |
| $^{31}_{15}P^{3 - }$ | 15 | 31 | 15 | 18 | 16 | - 3 | Anion |