Question

1. fill in the table below for compounds with polyatomic ions. name: agno₃, sc(no₃)₃, caso₄, li₂cr₂o₇. formula: sodium chlorite, barium cyanide, aluminum permanganate, ammonium hydroxide

Explanation:

Step1: Identify polyatomic ions

For $Li_2Cr_2O_7$, the polyatomic ion is $Cr_2O_7^{2 -}$ (dichromate), and the name is lithium dichromate.
For $CaSO_4$, the polyatomic ion is $SO_4^{2 -}$ (sulfate), and the name is calcium sulfate.
For $Sc(NO_3)_3$, the polyatomic ion is $NO_3^{-}$ (nitrate), and the name is scandium(III) nitrate.
For $AgNO_3$, the polyatomic ion is $NO_3^{-}$ (nitrate), and the name is silver nitrate.
For ammonium hydroxide, the formula is $NH_4OH$ with polyatomic ions $NH_4^{+}$ (ammonium) and $OH^{-}$ (hydroxide).
For aluminum permanganate, the formula is $Al(MnO_4)_3$ with polyatomic ion $MnO_4^{-}$ (permanganate).
For barium cyanide, the formula is $Ba(CN)_2$ with polyatomic ion $CN^{-}$ (cyanide).
For sodium chlorite, the formula is $NaClO_2$ with polyatomic ion $ClO_2^{-}$ (chlorite).

Answer:

Name	Formula
Calcium Sulfate	$CaSO_4$
Scandium(III) Nitrate	$Sc(NO_3)_3$
Silver Nitrate	$AgNO_3$
Ammonium Hydroxide	$NH_4OH$
Aluminum Permanganate	$Al(MnO_4)_3$
Barium Cyanide	$Ba(CN)_2$
Sodium Chlorite	$NaClO_2$