QUESTION IMAGE
Question
- given: $overline{km}$ bisects $angle{jkl}$
prove: $mangle{mkl}=\frac{1}{2}mangle{jkl}$
| statements | reasons |
|---|---|
| 2. $mangle{jkm}=mangle{mkl}$ | 2. |
| 3. $mangle{jkm}+mangle{mkl}=mangle{jkl}$ | 3. |
| 4. $mangle{mkl}+mangle{mkl}=mangle{jkl}$ | 4. |
| 5. $2mangle{mkl}=mangle{jkl}$ | 5. |
| 6. $mangle{mkl}=\frac{1}{2}mangle{jkl}$ | 6. |
Step1: Given information
Given
Step2: Definition of angle - bisector
Definition of angle - bisector
Step3: Angle - addition postulate
Angle - addition postulate
Step4: Substitution property
Substitute \(m\angle JKM\) with \(m\angle MKL\)
Step5: Simplify the left - hand side
Combining like terms
Step6: Division property of equality
Divide both sides by 2
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| Statements | Reasons |
|---|---|
| 2. \(m\angle JKM=m\angle MKL\) | 2. Definition of angle - bisector |
| 3. \(m\angle JKM + m\angle MKL=m\angle JKL\) | 3. Angle - addition postulate |
| 4. \(m\angle MKL + m\angle MKL=m\angle JKL\) | 4. Substitution property |
| 5. \(2m\angle MKL=m\angle JKL\) | 5. Combining like terms |
| 6. \(m\angle MKL=\frac{1}{2}m\angle JKL\) | 6. Division property of equality |