Question

11, what is the current reading in the ammeter in this circuit?
v = 3.0 v
r = 250 mω

1. draw a circuit that has two 1.5 v batteries in series, a 0.5 ω resistor, a switch and an ammeter. what is the current reading in the ammeter?

Explanation:

Question 11

Step1: Convert resistance to ohms

The resistance \( R = 250 \, \text{m}\Omega \). Since \( 1 \, \text{m}\Omega = 10^{-3} \, \Omega \), we have \( R = 250 \times 10^{-3} \, \Omega = 0.25 \, \Omega \).

Step2: Apply Ohm's Law (\( I = \frac{V}{R} \))

Given \( V = 3.0 \, \text{V} \) and \( R = 0.25 \, \Omega \), substitute into the formula: \( I = \frac{3.0}{0.25} \).

Step3: Calculate the current

\( \frac{3.0}{0.25} = 12 \, \text{A} \).

Step1: Calculate total voltage

Two \( 1.5 \, \text{V} \) batteries in series: \( V_{\text{total}} = 1.5 + 1.5 = 3.0 \, \text{V} \).

Step2: Identify resistance

Resistor \( R = 0.5 \, \Omega \).

Step3: Apply Ohm's Law (\( I = \frac{V}{R} \))

Substitute \( V = 3.0 \, \text{V} \) and \( R = 0.5 \, \Omega \): \( I = \frac{3.0}{0.5} \).

Step4: Calculate the current

\( \frac{3.0}{0.5} = 6 \, \text{A} \).

Answer:

The current reading in the ammeter is \( 12 \, \text{A} \).

Question 12