Question

1. a 12.00 - liter box had 4.50 moles of chlorine gas. if 2.00 moles of chlorine gas entered the box, what is the new volume of the box, assuming pressure and temperature stayed constant.

Explanation:

Step1: Calculate new number of moles

The initial number of moles $n_1 = 4.50$ moles and 2.00 moles are added. So the new number of moles $n_2=n_1 + 2.00=4.50+2.00 = 6.50$ moles.

Step2: Apply Avogadro's law

Avogadro's law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$, where $V_1 = 12.00$ L, $n_1 = 4.50$ moles and $n_2=6.50$ moles. We can solve for $V_2$. Rearranging the formula gives $V_2=\frac{V_1\times n_2}{n_1}$.
Substitute the values: $V_2=\frac{12.00\times6.50}{4.50}=\frac{78}{4.50}\approx17.33$ L.

Answer:

$17.33$ L