Question

12/22
factor $k^2+7k+10$
$(k+2)(k-5)$
$(k-2)(k-5)$
$(k+2)(k+5)$
$(k+10)(k+4)$

Explanation:

Step1: Identify quadratic form

We factor $k^2+7k+10$ (note: the $x$ is likely a typo for $k$). We need two numbers that multiply to $10$ and add to $7$.

Step2: Find factor pairs

The numbers $2$ and $5$ satisfy: $2\times5=10$, $2+5=7$.

Step3: Write factored form

Substitute into binomial factors: $(k+2)(k+5)$

Answer:

$(k+2)(k+5)$