Question

1. determine the centripetal force of a 2,500 kg car driving around a curved road with a tangential velocity of 15.64 m/s. the car is traveling 22 m from the center of the circle created by the roads curve.

○ 3500 n
○ 1800 n
○ 28,000 n
○ 77,000 n

Explanation:

Step1: Recall centripetal force formula

$F_c = \frac{mv^2}{r}$

Step2: Identify given values

$m=2500\ \text{kg}$, $v=15.64\ \text{m/s}$, $r=22\ \text{m}$

Step3: Calculate $v^2$

$v^2 = (15.64)^2 = 244.6096\ \text{m}^2/\text{s}^2$

Step4: Substitute values into formula

$F_c = \frac{2500 \times 244.6096}{22}$

Step5: Compute the final value

$F_c = \frac{611524}{22} \approx 3500\ \text{N}$

Answer:

3500 N