Question

1. the element titanium occurs naturally as five different isotopes: ^46ti (45.9526316amu; 8.25%), ^47ti (46.9517631; 7.44%), ^48ti (47.9479463; 73.7%), ^49ti (48.9478700; 5.41%), ^50ti (49.9447912; 5.18%). calculate the average atomic mass of titanium.

Explanation:

Step1: Convert percentages to decimals

$8.25\% = 0.0825$, $7.44\%=0.0744$, $73.7\% = 0.737$, $5.41\%=0.0541$, $5.18\% = 0.0518$

Step2: Multiply mass of each isotope by its abundance

For $^{46}\text{Ti}$: $45.9526316\times0.0825 = 3.791192117$
For $^{47}\text{Ti}$: $46.9517631\times0.0744 = 3.493211175$
For $^{48}\text{Ti}$: $47.9479463\times0.737 = 35.33763642$
For $^{49}\text{Ti}$: $48.9478700\times0.0541 = 2.648089767$
For $^{50}\text{Ti}$: $49.9447912\times0.0518 = 2.586140184$

Step3: Sum up the products

$3.791192117+3.493211175 + 35.33763642+2.648089767+2.586140184=47.85626966$

Answer:

$47.86$ amu (rounded to two - decimal places)