Question

1. find the area of a trapezoid with bases 2 ft and 3 ft and height \\(\frac{1}{4}\\) ft.\

\\(\circ\\) \\(\frac{4}{5}\\) \\(\text{ft}^2\\)\
\\(\circ\\) \\(\frac{3}{4}\\) \\(\text{ft}^2\\)\
\\(\circ\\) \\(\frac{3}{8}\\) \\(\text{ft}^2\\)\
\\(\circ\\) \\(\frac{5}{8}\\) \\(\text{ft}^2\\)

Explanation:

Step1: Recall trapezoid area formula

Area = $\frac{1}{2}(b_1 + b_2)h$

Step2: Substitute values

$b_1=2$, $b_2=3$, $h=\frac{1}{4}$
Area = $\frac{1}{2}(2 + 3)\times\frac{1}{4}$

Step3: Calculate sum of bases

$2 + 3 = 5$
Area = $\frac{1}{2}\times5\times\frac{1}{4}$

Step4: Compute final area

$\frac{5}{8}$

Answer:

$\frac{5}{8}\ \text{ft}^2$