Question

1. find sin d.

Explanation:

Step1: Recall sine definition

For an acute angle in a right triangle, $\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}}$

Step2: Identify sides for $\angle D$

Opposite side to $\angle D$ is $FE = 3$ cm, hypotenuse is $FD = 5$ cm.

Step3: Calculate $\sin D$

$\sin D = \frac{FE}{FD} = \frac{3}{5}$

Answer:

$\frac{3}{5}$ (corresponding to the first option: $\frac{3}{5}$)