Question

1. find the x- and y-intercepts for - 8x + 20y = 40 (2 pts)

Explanation:

Step1: Find x-intercept (set y=0)

Substitute \( y = 0 \) into \( -8x + 20y = 40 \):
\( -8x + 20(0) = 40 \)
Simplify: \( -8x = 40 \)
Solve for \( x \): \( x = \frac{40}{-8} = -5 \)

Step2: Find y-intercept (set x=0)

Substitute \( x = 0 \) into \( -8x + 20y = 40 \):
\( -8(0) + 20y = 40 \)
Simplify: \( 20y = 40 \)
Solve for \( y \): \( y = \frac{40}{20} = 2 \)

Answer:

x-intercept: \( -5 \), y-intercept: \( 2 \)