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Question
#12 m∠gkh =
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this is a required question
#13 m∠mnq =
Step1: Assume the two angles are supplementary
If the two angles $\angle{JGK}=(13x - 1)^{\circ}$ and $\angle{GKH}=(9x + 3)^{\circ}$ are supplementary (form a straight - line), then their sum is $180^{\circ}$. So, $(13x-1)+(9x + 3)=180$.
Step2: Simplify the left - hand side of the equation
Combine like terms: $13x+9x-1 + 3=180$, which gives $22x+2 = 180$.
Step3: Solve for x
Subtract 2 from both sides: $22x=180 - 2=178$. Then $x=\frac{178}{22}=\frac{89}{11}\approx8.09$.
Step4: Find the measure of $\angle{GKH}$
Substitute $x$ into the expression for $\angle{GKH}$: $m\angle{GKH}=(9x + 3)^{\circ}$. Plugging in $x=\frac{89}{11}$, we have $9\times\frac{89}{11}+3=\frac{801}{11}+3=\frac{801+33}{11}=\frac{834}{11}\approx75.82^{\circ}$.
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$\frac{834}{11}^{\circ}$ (or approximately $75.82^{\circ}$)