Question

1. how are the codes (chemical formulas) for
2. use what you have just learned about chemical formulas to identify each of the following as an

element, a compound or a mixture.
a. br₂ \t\tb. nahco₃ \t\tc. c₆h₁₂o₆ & h₂o
\t\t\te. co₂ \t\t\tf. al

Explanation:

To solve this, we recall the definitions:

• Element: Consists of only one type of atom (chemical symbol of one element).
• Compound: Consists of two or more different elements chemically bonded (formula has multiple elements).
• Mixture: Consists of two or more substances (compounds/elements) physically mixed (formula shows multiple compounds).

Part (a): $\boldsymbol{\ce{Br_2}}$

• $\ce{Br}$ is the symbol for bromine. $\ce{Br_2}$ has only bromine atoms (diatomic molecule of the element bromine).
• Classification: Element

Part (b): $\boldsymbol{\ce{NaHCO_3}}$

• Formula has $\ce{Na}$ (sodium), $\ce{H}$ (hydrogen), $\ce{C}$ (carbon), $\ce{O}$ (oxygen) – multiple different elements bonded.
• Classification: Compound

Part (c): $\boldsymbol{\ce{C_6H_{12}O_6}}$ & $\boldsymbol{\ce{H_2O}}$

• Two distinct compounds ($\ce{C_6H_{12}O_6}$ is glucose; $\ce{H_2O}$ is water) are mixed (not chemically bonded).
• Classification: Mixture

Part (e): $\boldsymbol{\ce{CO_2}}$

• Formula has $\ce{C}$ (carbon) and $\ce{O}$ (oxygen) – two different elements bonded.
• Classification: Compound

Part (f): $\boldsymbol{\ce{Al}}$

• $\ce{Al}$ is the symbol for aluminum, consisting of only aluminum atoms.
• Classification: Element

Final Answers:

a. $\ce{Br_2}$: Element
b. $\ce{NaHCO_3}$: Compound
c. $\ce{C_6H_{12}O_6}$ & $\ce{H_2O}$: Mixture
e. $\ce{CO_2}$: Compound
f. $\ce{Al}$: Element

Answer:

To solve this, we recall the definitions:

• Element: Consists of only one type of atom (chemical symbol of one element).
• Compound: Consists of two or more different elements chemically bonded (formula has multiple elements).
• Mixture: Consists of two or more substances (compounds/elements) physically mixed (formula shows multiple compounds).

Part (a): $\boldsymbol{\ce{Br_2}}$

• $\ce{Br}$ is the symbol for bromine. $\ce{Br_2}$ has only bromine atoms (diatomic molecule of the element bromine).
• Classification: Element

Part (b): $\boldsymbol{\ce{NaHCO_3}}$

• Formula has $\ce{Na}$ (sodium), $\ce{H}$ (hydrogen), $\ce{C}$ (carbon), $\ce{O}$ (oxygen) – multiple different elements bonded.
• Classification: Compound

Part (c): $\boldsymbol{\ce{C_6H_{12}O_6}}$ & $\boldsymbol{\ce{H_2O}}$

• Two distinct compounds ($\ce{C_6H_{12}O_6}$ is glucose; $\ce{H_2O}$ is water) are mixed (not chemically bonded).
• Classification: Mixture

Part (e): $\boldsymbol{\ce{CO_2}}$

• Formula has $\ce{C}$ (carbon) and $\ce{O}$ (oxygen) – two different elements bonded.
• Classification: Compound

Part (f): $\boldsymbol{\ce{Al}}$

• $\ce{Al}$ is the symbol for aluminum, consisting of only aluminum atoms.
• Classification: Element

Final Answers:

a. $\ce{Br_2}$: Element
b. $\ce{NaHCO_3}$: Compound
c. $\ce{C_6H_{12}O_6}$ & $\ce{H_2O}$: Mixture
e. $\ce{CO_2}$: Compound
f. $\ce{Al}$: Element