Question

1. solve $|2x + 1| \geq 0$
2. solve $|6 - 5x| < -4$

Explanation:

Step1: Recall absolute value property

The absolute value of any real number $|a|$ is always non-negative, meaning $|a| \geq 0$ for all real $a$.

Step2: Apply to given inequality

For $|2x+1| \geq 0$, since $2x+1$ is a real number for all real $x$, this inequality holds for every real $x$.

Step3: Analyze the second inequality

For $|6-5x| < -4$, the absolute value of any real number cannot be negative, so there is no real $x$ that satisfies this.

Answer:

1. All real numbers (or $(-\infty, \infty)$)
2. No real solution (or $\emptyset$)