QUESTION IMAGE
Question
- -4(-8x - 8)
- -6(7 + x)
- -9(x - 8)
- -8(10x + 1)
- (1 + 2x)·5
- -8(1 - 5x)
- -7(5k - 4)
- -5(7a - 6)
- 5(n + 6)
- 4(3r - 8)
- 3(5 + 5x)
- (1 + 9x)·-10
All problems use the distributive property: $a(b+c)=ab+ac$ or $a(b-c)=ab-ac$, including handling negative coefficients.
14: Distribute $-6$ to terms inside
$-6(7+x) = (-6)(7) + (-6)(x)$
$=-42 -6x$
15: Distribute $-3$ to terms inside
$-3(x-5) = (-3)(x) + (-3)(-5)$
$=-3x +15$
16: Distribute $-5$ to terms inside
$-5(10x+1) = (-5)(10x) + (-5)(1)$
$=-50x -5$
17: Distribute $5$ to terms inside
$(1+2x)\cdot5 = (1)(5) + (2x)(5)$
$=5 +10x$
18: Distribute $-8$ to terms inside
$-8(1-5x) = (-8)(1) + (-8)(-5x)$
$=-8 +40x$
19: Distribute $-7$ to terms inside
$-7(5k-4) = (-7)(5k) + (-7)(-4)$
$=-35k +28$
20: Distribute $-5$ to terms inside
$-5(7a-6) = (-5)(7a) + (-5)(-6)$
$=-35a +30$
21: Distribute $5$ to terms inside
$5(m+6) = (5)(m) + (5)(6)$
$=5m +30$
22: Distribute $4$ to terms inside
$4(3r-8) = (4)(3r) + (4)(-8)$
$=12r -32$
23: Distribute $3$ to terms inside
$3(5+5x) = (3)(5) + (3)(5x)$
$=15 +15x$
24: Distribute $-10$ to terms inside
$(1+9x)\cdot-10 = (1)(-10) + (9x)(-10)$
$=-10 -90x$
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- $\boldsymbol{-42 -6x}$
- $\boldsymbol{-3x +15}$
- $\boldsymbol{-50x -5}$
- $\boldsymbol{5 +10x}$
- $\boldsymbol{-8 +40x}$
- $\boldsymbol{-35k +28}$
- $\boldsymbol{-35a +30}$
- $\boldsymbol{5m +30}$
- $\boldsymbol{12r -32}$
- $\boldsymbol{15 +15x}$
- $\boldsymbol{-10 -90x}$
(Note: Problem 13 is cut off and cannot be solved with the provided image content)