Question

1. in the compound ch₃oh the shape around the c atom is ⅰ and the shape around the o atom is ⅱ. the statement above is best completed by the answers in row:

row	ⅰ	ⅱ
	tetrahedral	linear
	trigonal pyramidal	bent
	tetrahedral	bent

Explanation:

Step1: Analyze C - atom bonding in $CH_3OH$

The carbon atom in $CH_3OH$ is bonded to 4 other atoms (3 H - atoms and 1 O - atom). According to VSEPR (Valence - Shell Electron - Pair Repulsion) theory, when a central atom has 4 bonding pairs and 0 lone pairs, the molecular geometry is tetrahedral.

Step2: Analyze O - atom bonding in $CH_3OH$

The oxygen atom in $CH_3OH$ is bonded to 2 atoms (1 C - atom and 1 H - atom) and has 2 lone pairs. According to VSEPR theory, when a central atom has 2 bonding pairs and 2 lone pairs, the molecular geometry is bent.

Answer:

tetrahedral, bent