Question

1. 2 s + fe₂o₃ → fe + so₂

Explanation:

Step1: Balance oxygen atoms

Let the coefficient of $Fe_2O_3$ be $x$, the coefficient of $SO_2$ be $y$. The number of oxygen atoms in $Fe_2O_3$ is $3x$ and in $SO_2$ is $2y$. For oxygen - atom balance, assume the reaction equation is $2S + xFe_2O_3
ightarrow zFe + ySO_2$.
The oxygen - atom balance gives $3x = 2y$. Let's start with the smallest non - zero integers. If $x = 2$, then $y = 3$.
The equation becomes $2S+2Fe_2O_3
ightarrow zFe + 3SO_2$.

Step2: Balance iron atoms

In $2Fe_2O_3$, the number of iron atoms is $4$. So, for iron - atom balance, $z = 4$.
The balanced chemical equation is $2S + 2Fe_2O_3
ightarrow4Fe+3SO_2$.

Answer:

$2S + 2Fe_2O_3
ightarrow4Fe + 3SO_2$ (coefficients are 2, 2, 4, 3)