Question

13x - 11 ≤ 7x + 37

Explanation:

Step1: Subtract \(7x\) from both sides

To isolate the \(x\) terms on one side, we subtract \(7x\) from both sides of the inequality \(13x - 11\leq7x + 37\). This gives us \((13x - 7x)- 11\leq(7x - 7x)+ 37\), which simplifies to \(6x - 11\leq37\).

Step2: Add 11 to both sides

Next, we add 11 to both sides of the inequality \(6x - 11\leq37\) to isolate the term with \(x\). So, \(6x- 11 + 11\leq37 + 11\), which simplifies to \(6x\leq48\).

Step3: Divide both sides by 6

Finally, we divide both sides of the inequality \(6x\leq48\) by 6 to solve for \(x\). This gives us \(\frac{6x}{6}\leq\frac{48}{6}\), which simplifies to \(x\leq8\).

Answer:

\(x\leq8\)