QUESTION IMAGE
Question
- factor $4m^{2}-1$:
a. $(2m+1)^{2}$
b. $(2m-1)^{2}$
c. $(2m+1)(2m-1)$
d. $(-2m+1)(2m-1)$
Step1: Recognize difference of squares
$4m^2 - 1 = (2m)^2 - 1^2$
Step2: Apply difference of squares formula
Recall $a^2 - b^2 = (a+b)(a-b)$. Here $a=2m$, $b=1$.
$\implies (2m+1)(2m-1)$
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c. $(2m+1)(2m-1)$