Question

1. given the graph below, find gh.

Explanation:

Step1: Identify coordinates

Let the coordinates of point $G$ be $(- 4,3)$ and of point $H$ be $(3,0)$ from the graph.

Step2: Apply distance - formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-4,y_1 = 3,x_2=3,y_2 = 0$.
\[

$$\begin{align*} d&=\sqrt{(3-(-4))^2+(0 - 3)^2}\\ &=\sqrt{(3 + 4)^2+( - 3)^2}\\ &=\sqrt{7^2+(-3)^2}\\ &=\sqrt{49 + 9}\\ &=\sqrt{58} \end{align*}$$

\]

Answer:

$\sqrt{58}$