Question

1. factor ( 9n + 6 ).

a. ( 6(n + 1) )
b. ( 3(3n + 2) )
c. ( 3(n + 2) )
d. ( 3(3n + 1) )

Explanation:

Step1: Find GCD of terms

GCD of 9 and 6 is 3.

Step2: Factor out GCD

$9n + 6 = 3\times3n + 3\times2 = 3(3n + 2)$

Answer:

b. $3(3n + 2)$