Question

1. find the product ((x + 3)^3).

(circ) (x^3 + 9x^2 + 27x + 27)
(circ) (x^3 + 27x^2 + 9x + 27)
(circ) (x^3 + 27)
(circ) (x^3 + 3x^3 + 9x + 27)

Explanation:

Step1: Recall binomial cube formula

The formula for $(a+b)^3$ is $a^3 + 3a^2b + 3ab^2 + b^3$.

Step2: Substitute $a=x$, $b=3$

$$(x+3)^3 = x^3 + 3x^2(3) + 3x(3)^2 + 3^3$$

Step3: Calculate each term

$$= x^3 + 9x^2 + 27x + 27$$

Answer:

$\boldsymbol{x^3 + 9x^2 + 27x + 27}$ (corresponding to the first option)