15) how many grams are in 4.5 moles of sodium fluoride, naf?
16) how many moles are in 98.3 grams of aluminum hydroxide, al(oh)₃?
17) how many grams are in 0.02 moles of beryllium iodide, bei₂?
18) how many moles are in 68 grams of copper (ii) hydroxide, cu(oh)₂?
19) how many grams are in 3.3 moles of potassium sulfide, k₂s?
20) how many moles are in 1.2 x 10³ grams of ammonia, nh₃?
21) how many grams are in 2.3 x 10⁻⁴ moles of calcium phosphate, ca₃(po₃)₂?
22) how many moles are in 3.4 x 10⁻⁷ grams of silicon dioxide, sio₂?
23) how many grams are in 1.11 moles of manganese sulfate, mn₃(so₄)₇?

Question

Accepted Answer

### Question 15: How many grams are in 4.5 moles of sodium fluoride, NaF?
# Explanation:
## Step 1: Calculate molar mass of NaF
Molar mass of Na = 22.99 g/mol, F = 19.00 g/mol.
Molar mass of NaF = 22.99 + 19.00 = 41.99 g/mol.
## Step 2: Use moles to grams formula ($	ext{mass} = 	ext{moles} 	imes 	ext{molar mass}$)
Mass = 4.5 mol × 41.99 g/mol ≈ 188.96 g.
# Answer:
Approximately 189 grams (or 188.96 g)

### Question 16: How many moles are in 98.3 grams of aluminum hydroxide, $	ext{Al(OH)}_3$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{Al(OH)}_3$
Al = 26.98 g/mol, O = 16.00 g/mol, H = 1.01 g/mol.
Molar mass = 26.98 + 3×(16.00 + 1.01) = 26.98 + 3×17.01 = 26.98 + 51.03 = 78.01 g/mol.
## Step 2: Use grams to moles formula ($	ext{moles} = \frac{	ext{mass}}{	ext{molar mass}}$)
Moles = $\frac{98.3\ 	ext{g}}{78.01\ 	ext{g/mol}} \approx 1.26\ 	ext{mol}$.
# Answer:
Approximately 1.26 moles

### Question 17: How many grams are in 0.02 moles of beryllium iodide, $	ext{BeI}_2$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{BeI}_2$
Be = 9.01 g/mol, I = 126.90 g/mol.
Molar mass = 9.01 + 2×126.90 = 9.01 + 253.80 = 262.81 g/mol.
## Step 2: Use moles to grams formula
Mass = 0.02 mol × 262.81 g/mol = 5.2562 g ≈ 5.26 g.
# Answer:
Approximately 5.26 grams

### Question 18: How many moles are in 68 grams of copper (II) hydroxide, $	ext{Cu(OH)}_2$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{Cu(OH)}_2$
Cu = 63.55 g/mol, O = 16.00 g/mol, H = 1.01 g/mol.
Molar mass = 63.55 + 2×(16.00 + 1.01) = 63.55 + 2×17.01 = 63.55 + 34.02 = 97.57 g/mol.
## Step 2: Use grams to moles formula
Moles = $\frac{68\ 	ext{g}}{97.57\ 	ext{g/mol}} \approx 0.697\ 	ext{mol} \approx 0.70\ 	ext{mol}$.
# Answer:
Approximately 0.70 moles (or 0.697 mol)

### Question 19: How many grams are in 3.3 moles of potassium sulfide, $	ext{K}_2	ext{S}$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{K}_2	ext{S}$
K = 39.10 g/mol, S = 32.07 g/mol.
Molar mass = 2×39.10 + 32.07 = 78.20 + 32.07 = 110.27 g/mol.
## Step 2: Use moles to grams formula
Mass = 3.3 mol × 110.27 g/mol ≈ 363.89 g ≈ 364 g.
# Answer:
Approximately 364 grams (or 363.89 g)

### Question 20: How many moles are in $1.2 	imes 10^3$ grams of ammonia, $	ext{NH}_3$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{NH}_3$
N = 14.01 g/mol, H = 1.01 g/mol.
Molar mass = 14.01 + 3×1.01 = 14.01 + 3.03 = 17.04 g/mol.
## Step 2: Use grams to moles formula
Moles = $\frac{1.2 	imes 10^3\ 	ext{g}}{17.04\ 	ext{g/mol}} \approx 70.43\ 	ext{mol}$.
# Answer:
Approximately 70.4 moles (or 70.43 mol)

### Question 21: How many grams are in $2.3 	imes 10^{-4}$ moles of calcium phosphate, $	ext{Ca}_3(	ext{PO}_3)_2$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{Ca}_3(	ext{PO}_3)_2$
Ca = 40.08 g/mol, P = 30.97 g/mol, O = 16.00 g/mol.
Molar mass = 3×40.08 + 2×(30.97 + 3×16.00)
= 120.24 + 2×(30.97 + 48.00)
= 120.24 + 2×78.97
= 120.24 + 157.94
= 278.18 g/mol.
## Step 2: Use moles to grams formula
Mass = $2.3 	imes 10^{-4}\ 	ext{mol} 	imes 278.18\ 	ext{g/mol} \approx 0.06398\ 	ext{g} \approx 0.064\ 	ext{g}$.
# Answer:
Approximately 0.064 grams (or 0.0640 g)

### Question 22: How many moles are in $3.4 	imes 10^{-7}$ grams of silicon dioxide, $	ext{SiO}_2$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{SiO}_2$
Si = 28.09 g/mol, O = 16.00 g/mol.
Molar mass = 28.09 + 2×16.00 = 28.09 + 32.00 = 60.09 g/mol.
## Step 2: Use grams to moles formula
Moles = $\frac{3.4 	imes 10^{-7}\ 	ext{g}}{60.09\ 	ext{g/mol}} \approx 5.66 	imes 10^{-9}\ 	ext{mol}$.
# Answer:
Approximately $5.7 	imes 10^{-9}$ moles (or $5.66 	imes 10^{-9}\ 	ext{mol}$)

### Question 23: How many grams are in 1.11 moles of manganese sulfate, $	ext{Mn}_3(	ext{SO}_4)_7$?
# Explanation:
## Step 1: Calculate molar mass of $	ext{Mn}_3(	ext{SO}_4)_7$
Mn = 54.94 g/mol, S = 32.07 g/mol, O = 16.00 g/mol.
Molar mass = 3×54.94 + 7×(32.07 + 4×16.00)
= 164.82 + 7×(32.07 + 64.00)
= 164.82 + 7×96.07
= 164.82 + 672.49
= 837.31 g/mol.
## Step 2: Use moles to grams formula
Mass = 1.11 mol × 837.31 g/mol ≈ 929.41 g.
# Answer:
Approximately 929 grams (or 929.41 g)

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QUESTION IMAGE

Question

Explanation:

Question 15: How many grams are in 4.5 moles of sodium fluoride, NaF?

Step 1: Calculate molar mass of NaF

Step 2: Use moles to grams formula ($\text{mass} = \text{moles} \times \text{molar mass}$)

Step 1: Calculate molar mass of $\text{Al(OH)}_3$

Step 2: Use grams to moles formula ($\text{moles} = \frac{\text{mass}}{\text{molar mass}}$)

Step 1: Calculate molar mass of $\text{BeI}_2$

Step 2: Use moles to grams formula

Answer:

Question 16: How many moles are in 98.3 grams of aluminum hydroxide, $\text{Al(OH)}_3$?