Question

a 15.0 kg bike is moving with a force of 125 n. there is a -20.0 n force due to friction. what is the acceleration of the bike? a = ? m/s² hint: $f_{net} = m \cdot a$ remember to indicate positive (+) or negative (-) acceleration.

Explanation:

Step1: Calculate net force

Net force \( F_{net} = F_{applied} + F_{friction} = 125\ N + (-20.0\ N) = 105\ N \)

Step2: Use \( F_{net} = m \cdot a \) to find acceleration

Rearrange formula: \( a = \frac{F_{net}}{m} \)
Substitute values: \( a = \frac{105\ N}{15.0\ kg} = 7.00\ m/s^2 \)

Answer:

\( +7.00 \) (or \( 7.00 \))