Question

a 15.0 kg cart is moving over a horizontal surface while experiencing one rightward and two leftward forces. the rightward force has a magnitude of 25n, and the leftward forces have magnitudes of 11n and 14n, respectively. while experiencing these forces, the cart is displaced 52.0 meters in 13.0 seconds. what is true about the cart? check all that apply the cart is experiencing balanced forces in opposite directions the cart is experiencing unbalanced forces in opposite directions the cart is in static equilibrium the cart is in dynamic equilibrium the cart is not in equilibrium the carts velocity equals 52.0 meters divided by 13.0 seconds the carts velocity equals 52.0 meters multiplied by 13.0 seconds the carts velocity can not be determined

Explanation:

Step1: Calculate net force

The right - ward force $F_{right}=25N$, and the left - ward forces are $F_{left1}=11N$ and $F_{left2}=14N$. The net force $F_{net}=F_{right}-(F_{left1} + F_{left2})=25-(11 + 14)=25 - 25=0N$.

Step2: Analyze equilibrium

Since $F_{net}=0N$, the forces in the horizontal direction are balanced. The cart is moving with a displacement of $d = 52.0m$ in $t = 13.0s$. If the net force is zero, the cart is in dynamic equilibrium (because it is moving). The average velocity $v=\frac{d}{t}=\frac{52.0}{13.0}=4m/s$.

Answer:

The cart is experiencing balanced forces in opposite directions
The cart is in dynamic equilibrium
The cart's velocity equals 52.0 meters divided by 13.0 seconds