Question

a 15.0 kg chair has a net force of -120 n exerted onto it. what is the acceleration of the chair? image of a chair with a force arrow f = -120 n a = ? m/s² remember to indicate direction (+ or -) and magnitude.

Explanation:

Step1: Recall Newton's Second Law

Newton's second law states that \( F = ma \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration. We need to solve for \( a \), so we can rearrange the formula to \( a=\frac{F}{m} \).

Step2: Substitute the given values

We are given that \( F = - 120\space N \) and \( m = 15.0\space kg \). Substituting these values into the formula for acceleration, we get \( a=\frac{-120\space N}{15.0\space kg} \).

Step3: Calculate the acceleration

Dividing \(- 120\) by \(15.0\), we get \( a=- 8.0\space m/s^{2} \). The negative sign indicates the direction of the acceleration, which is consistent with the direction of the net force.

Answer:

\(-8.0\)