Question

15 ≥ \\(\frac{5}{3}(d - 6)\\) write and solve an inequa

Explanation:

Step1: Multiply both sides by 3

To eliminate the fraction, multiply both sides of the inequality \(15 \geq \frac{5}{3}(d - 6)\) by 3.
\(15\times3 \geq \frac{5}{3}(d - 6)\times3\)
\(45 \geq 5(d - 6)\)

Step2: Divide both sides by 5

Divide both sides of the inequality \(45 \geq 5(d - 6)\) by 5 to simplify.
\(\frac{45}{5} \geq \frac{5(d - 6)}{5}\)
\(9 \geq d - 6\)

Step3: Add 6 to both sides

Add 6 to both sides of the inequality \(9 \geq d - 6\) to solve for \(d\).
\(9 + 6 \geq d - 6 + 6\)
\(15 \geq d\) or \(d \leq 15\)

Answer:

\(d \leq 15\)