QUESTION IMAGE
Question
15x=-225=-15
-\frac{3}{2}u = - 3=
48 = 16x=
-45=\frac{9}{5}x=
360=-18n=
-3z = 72=
15=\frac{5}{6}x=
-\frac{12}{7}y=-36=
Step1: Isolate the variable for each equation
For the equation \(15x=-225\), divide both sides by 15: \(x = \frac{-225}{15}=-15\).
For the equation \(-\frac{3}{2}u=-3\), multiply both sides by \(-\frac{2}{3}\): \(u=-3\times(-\frac{2}{3}) = 2\).
For the equation \(48 = 16x\), divide both sides by 16: \(x=\frac{48}{16}=3\).
For the equation \(-45=\frac{9}{5}x\), multiply both sides by \(\frac{5}{9}\): \(x=-45\times\frac{5}{9}=-25\).
For the equation \(360=-18n\), divide both sides by - 18: \(n=\frac{360}{-18}=-20\).
For the equation \(-3z = 72\), divide both sides by - 3: \(z=\frac{72}{-3}=-24\).
For the equation \(15=\frac{5}{6}x\), multiply both sides by \(\frac{6}{5}\): \(x=15\times\frac{6}{5}=18\).
For the equation \(-\frac{12}{7}y=-36\), multiply both sides by \(-\frac{7}{12}\): \(y=-36\times(-\frac{7}{12}) = 21\).
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- \(x=-15\)
- \(u = 2\)
- \(x = 3\)
- \(x=-25\)
- \(n=-20\)
- \(z=-24\)
- \(x = 18\)
- \(y = 21\)