Question

(\frac{3}{2}k^{2}-16 = 80)

Explanation:

Step1: Add 16 to both sides

$\frac{3}{2}k^2 - 16 + 16 = 80 + 16$
$\frac{3}{2}k^2 = 96$

Step2: Multiply both sides by $\frac{2}{3}$

$\frac{2}{3} \times \frac{3}{2}k^2 = 96 \times \frac{2}{3}$
$k^2 = 64$

Step3: Take square root of both sides

$k = \pm\sqrt{64}$
$k = \pm 8$

Answer:

$k = 8$ or $k = -8$