Question

1. ac, df, and gl are parallel. use the figure to complete the proportion.

\\(\frac{jf}{fe}=\frac{?}{de}\\)
bc
jb
jd
ab

Explanation:

Step1: Apply similar - triangles property

Since $AC\parallel DF\parallel GI$, we can consider similar triangles formed by these parallel lines and the lines from the vertex $J$. Triangles $\triangle JFE$ and $\triangle JDE$ are related to other similar - triangles in the figure. By the property of similar triangles (when three parallel lines are intersected by two transversals, the ratios of corresponding segments are equal), we know that $\frac{JF}{FE}=\frac{JC}{CB}$ in the context of similar - triangles formed by the parallel lines $AC$, $DF$, and $GI$. Also, considering the relationship between the segments on the transversals, we know that $\frac{JF}{FE}=\frac{JB}{DE}$ because of the similarity of the triangles formed by the parallel lines.

Answer:

JB