Question

1. find the margin of error for a survey that has a sample size of 6400. round your answer to the nearest tenth of a percent. about ± 1 % correct answers: 17. find the margin of error for a survey that has a sample size of 3275. round your answer to the nearest tenth of a percent. about ± 1 % correct answers: 18. find the margin of error for a survey that has a sample size of 750. round your answer to the nearest tenth of a percent. about ± 1 %

Explanation:

Step1: Recall margin - of - error formula

For a simple random sample, the approximate margin of error (as a percentage) is given by $E=\frac{1}{\sqrt{n}}\times100\%$, where $n$ is the sample size.

Step2: Solve for question 16

Given $n = 6400$. Substitute into the formula: $E=\frac{1}{\sqrt{6400}}\times100\%$. Since $\sqrt{6400}=80$, then $E=\frac{1}{80}\times100\% = 1.25\%\approx1.3\%$.

Step3: Solve for question 17

Given $n = 3275$. Substitute into the formula: $E=\frac{1}{\sqrt{3275}}\times100\%$. $\sqrt{3275}\approx57.23$, so $E=\frac{1}{57.23}\times100\%\approx1.75\%\approx1.8\%$.

Step4: Solve for question 18

Given $n = 750$. Substitute into the formula: $E=\frac{1}{\sqrt{750}}\times100\%$. $\sqrt{750}\approx27.39$, so $E=\frac{1}{27.39}\times100\%\approx3.65\%\approx3.7\%$.

Answer:

1. about $\pm1.3\%$
2. about $\pm1.8\%$
3. about $\pm3.7\%$