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Question
- what is the solution to the inequality $4x - 1 \leq 11?$
a. $x \leq 3$
b. $x \geq 2.5$
c. $x \leq 2.5$
d. $x \geq 3$
Step1: Add 1 to both sides
$4x - 1 + 1 \leq 11 + 1$
$4x \leq 12$
Step2: Divide by 4 on both sides
$\frac{4x}{4} \leq \frac{12}{4}$
$x \leq 3$
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a. $x \leq 3$