Question

1. which of the following shows the correct number of atoms of each element in the formula mg(no₃)₂? 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms 1 magnesium atom, 1 nitrogen atoms, and 6 oxygen atoms 1 magnesium atom, 2 nitrogen atoms, and 5 oxygen atoms 1 magnesium atom, 1 nitrogen atoms, and 5 oxygen atoms clear all

Explanation:

To determine the number of atoms in \( \text{Mg(NO}_3\text{)}_2 \), we analyze each element:

• Magnesium (Mg): There is 1 Mg atom (no subscript or coefficient modifying it outside the parentheses).
• Nitrogen (N): Inside the parentheses, \( \text{NO}_3 \) has 1 N atom, and the subscript 2 outside the parentheses multiplies the entire \( \text{NO}_3 \) group. So, \( 1\times2 = 2 \) N atoms.
• Oxygen (O): Inside the parentheses, \( \text{NO}_3 \) has 3 O atoms, and the subscript 2 outside multiplies this. So, \( 3\times2 = 6 \) O atoms.

This matches the first option: 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms.

Answer:

1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms (the first option)